Abstract
In this paper we give a streamlined proof of an inequality recently obtained by the author: For every a a α∈(0,1) there exists a constant C = C(α,d)>0 such that for all u∈ Lq(Rd) for some 1 ≤ q < d/(1-α) such that Dαu :ΔI1-αu∈L1(Rd; Rd). We also give a counterexample which shows that in contrast to the case α=1, the fractional gradient does not admit an L1 trace inequality, i.e. ||Dαu||L1(Rd; Rd) cannot control the integral of u with respect to the Hausdorff content H∞ d-α. The main substance of this counterexample is a result of interest in its own right, that even a weak-type estimate for the Riesz transforms fails on the space L1(H∞ d-α),β∈[1,d).It is an open question whether this failure of a weak-type estimate for the Riesz transforms extends to β∈(0,1).
| Original language | English |
|---|---|
| Pages (from-to) | 153-168 |
| Number of pages | 16 |
| Journal | Portugaliae Mathematica |
| Volume | 76 |
| Issue number | 2 |
| DOIs | |
| Publication status | Published - 2019 |
| Externally published | Yes |
Keywords
- L-Sobolev inequality
- Lorentz spaces
- Trace inequality
ASJC Scopus subject areas
- General Mathematics
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